the number is 1 if it can't be 4.
11+1=12
That's 3 digits and they are identical which is the same digit. :]
2007-01-14 16:10:44
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answer #1
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answered by Trav 1
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1 + 11 = 12
2007-01-14 20:50:46
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answer #2
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answered by sg 2
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1
2007-01-14 16:12:10
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answer #3
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answered by plunger 2
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enable abcd characterize the digits of the third quantity, so the cost of the third quantity is 1000a + 100b + 10c + d 4321 + 1234 + abcd = 12341 those digit of a million + 4 + d is a million, so d = 6 and a million + 4 + d = 11. The tens digit of two + 3 + c + a million (carried over from those column) is 4, so c = 8 and a pair of + 3 + c + a million = 14. the 1000's digit of three + 2 + b + a million is 3, so b = 7 and 3 + 2 + b + a million = thirteen. 4 + a million + a + a million = 12, so a = 6. The third quantity is 6788. ===== Whoops, I purely observed the backside 7 area. nicely, the technique is an identical,.
2016-12-13 06:53:30
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answer #4
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answered by Anonymous
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13
1+3+1+3+1+3=12
2007-01-14 16:11:43
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answer #5
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answered by Anonymous
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Maybe in a different base b:
x + x + x = 1*b + 2
3x = b + 2
This is a Diofantes equation. It has the solution
x = k
b = 3k - 2
Now, the digits can not be gretaer than the base, so
k =< 3k - 2 - 1
3 =< 2k
k >= 3/2
k => 2
we have 2 + 2 + 2 = 12 in base 4
3 + 3 + 3 = 12 in base 7
and so on
2007-01-15 01:43:29
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answer #6
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answered by Bushido The WaY of DA WaRRiOr 2
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It could be either of the following:
4+4+4 = 12
11+1 = 12
Bother have 3 digits, and both equal 12.
2007-01-14 16:13:41
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answer #7
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answered by Anonymous
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1 + 11 = 12 1 is the lucky number
2007-01-14 16:12:00
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answer #8
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answered by Shannon Kay 2
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11+1=12
2007-01-14 16:11:19
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answer #9
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answered by Always Question 3
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there are 3 ways ...
1+11=12
{ (2^2) ! } / 2 = 4! /2 = 24/2 =12
4 + 4+ 4 = 12
{33+3} / 3 =12 (four)
2007-01-14 16:18:56
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answer #10
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answered by KP-Rox 2
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the digits are 12 12 and -12
2007-01-14 16:11:52
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answer #11
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answered by A. Mapp 2
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