Two blocks are connected by a wire....?

Question

Two blocks are connected by a wire that has a mass per unit length of 8.50 X 10^-4 kg/m. One block has a mass of 19.0 kg, while the other has a mass of 42.0 kg. These blocks are being pulled across a horizontal frictionless floor by a horizontal force P that is applied to the less massive block. A transverse wave travels on the wire between the blocks with a speed of 352 m/s (relative to the wire). The mass of the wire is negligible compared to the mass of the blocks. Find the magnitude of P.


If you understand this, can you please tell me how you did it? Thanks!

Answer 1

let's start with a relationship of a speed of propagation (v), tension (T) and mass per unit length of the wire(u).

We have v=(T/u)^.5 or T=u v^2

T=(8.50 X 10^-4 kg/m) (352 m/s )^2=
T=105.32N

But T is not P
T is the force exerted on larger block
Also acceleration of both blocks must be the same so

a=T/m2

P=a(m1+m2) ignoring the weight of the spring.

P=T(m1+m2)/m2=
P105.32N(19+42)/42=153 N

I hope it helps :)

Answer 2

it is consistently secure to apply a seperate fuses for the two merely in case something does ensue yet you do not could you may merely take the foremost capacity and hook it to a minimum of one amp then run it off to the different and save one fuse and definite you're able to do an identical with the floor