How would you solve 3 squared + x squared = root 34 squared?
2007-01-14 13:10:17 · 6 answers · asked by Kate! 3 in Science & Mathematics ➔ Mathematics
wow that's the same thing I'm learning in school for math!!!
2007-01-14 13:18:27 · answer #1 · answered by queenosofly 3 · 0⤊ 0⤋
3^2 + x^2 = V`(34^2)
First: solve 3^2...
9 + x^2 = V`(34^2)
Sec: find the square root of 34^2...
9 + x^2 = 34
Third: subtract 9 from both sides...
9 - 9 + x^2 = 34 - 9
x^2 = 25
Fourth: eliminate the parenthesis and solve for "x" > find the square root of both sides...
V`(x^2) = +/- V`25
x = 5, -5
2007-01-14 21:26:41 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
ok
3^2 + X^2 = sr 34 ^2
so
9 + X^2 = 34
subtract 9 from both sides
X^2 = 34 - 9
X^2 = 25
solve for X taking square root of both sides
X = 5
2007-01-14 21:16:19 · answer #3 · answered by ignoramus 7 · 0⤊ 0⤋
Well, assuming that you mean "root 34 squared" means the square root of 34 squared...then the squaring would cancel out the square root. In that case, square three (3x3) and get 9+x squared equals 34. Get the nine out of there...minus it from both sides. That means that x squared is 25. so get the square out of there...the square root of xsquared would be x and the square root of 25 would be 5...so therefore x = 5.
2007-01-14 21:15:11 · answer #4 · answered by mcollum83 3 · 0⤊ 1⤋
3^2 + x^2 = 34^(1/2)(2)
= 9 + x^2 = 34
= x^2 = 25
so x = +/- 5
2007-01-14 21:20:40 · answer #5 · answered by davidosterberg1 6 · 1⤊ 0⤋
9 + x^2 = sqrt(34^2)
9 + x^2 = 34
x^2 = 25
x = sqrt(25)
x = 5
2007-01-14 21:16:05 · answer #6 · answered by RScott 3 · 0⤊ 0⤋