2007-01-14 12:28:49 · 7 answers · asked by melissa a 1 in Science & Mathematics ➔ Mathematics
general formula to factor the difference of perfect squares:
A^2 - B^2 = (A + B) (A -B)
36 Y^2 = (6Y)^2
25 A^2 = (5A)^2
so the answer is (6Y + 5A) (6Y - 5A)
2007-01-14 13:16:37 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
36y^2 - 25a^2
= (6y)^2 - (5a)^2
= (6y - 5a) . (6y + 5a)
(Difference of Perfect Squares)
2007-01-14 20:34:40 · answer #2 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
36y^2 - 25a^2 = (6y - 5a)(6y + 5a)
2007-01-14 20:56:59 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
(6y+5a)(6y-5a) Do your own math!
2007-01-14 20:46:13 · answer #4 · answered by Burton Dude 2 · 0⤊ 0⤋
36y^2-25a^2
=(6y)^2-(5a)^2
=(6y+5a)(6y-5a)
s
2007-01-14 20:53:28 · answer #5 · answered by alpha 7 · 0⤊ 0⤋
(6y-5a)(6y+5a)
2007-01-14 21:40:10 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(6y-5a)(6y+5a)
2007-01-14 20:31:45 · answer #7 · answered by zephrrrrrrrrrrr 2 · 0⤊ 0⤋