2007-01-14 12:02:14 · 10 answers · asked by blacksky515 1 in Science & Mathematics ➔ Chemistry
neutral Aluminum atom would have an atomic number of 13 so would have 13 electrons. A +3 charged Aluminum atom would have three less electrons to account for the +3 charge so an Aluminum +3 ion would have 10 electrons and the configuration would be 1s2, 2s2, 2p6 +3
2007-01-14 12:06:27 · answer #1 · answered by SPFN9 2 · 1⤊ 0⤋
Aluminum's atomic number is 13 and its electron configuration is 3sË2 3pË1. That's three s squared three p to the first power. And its electrons per shell are 2, 8, 3.
Hopefully that's what you were looking for.
2007-01-14 20:12:59 · answer #2 · answered by aint_the_dakota 1 · 0⤊ 0⤋
Elemental aluminum has the following electron configuration:
[Ne] 3s2 3p1
If you need the configuration for Neon, just fill out all of the sublevels until you get to 3s.
2007-01-14 20:06:57 · answer #3 · answered by Jess4352 5 · 0⤊ 0⤋
do you mean the electron spin notation? its going to be 2S1 2S2 6P2 2S3 1P3. Sounds right anyway.
2007-01-14 20:09:50 · answer #4 · answered by Roger N 2 · 0⤊ 0⤋
negative 7
2007-01-14 20:04:37 · answer #5 · answered by cese1 2 · 0⤊ 0⤋
+3..AL+3..cuz it has 3 valence e`, where it frees 3 e' to obtain stability...
2007-01-14 20:13:28 · answer #6 · answered by ....Baby witch.. 2 · 0⤊ 0⤋
2s8p3d
2007-01-14 20:06:26 · answer #7 · answered by QQ dri lu 4 · 0⤊ 0⤋
donna
2007-01-14 20:05:24 · answer #8 · answered by Anonymous · 0⤊ 0⤋
al
I think
2007-01-14 20:05:41 · answer #9 · answered by joeysgirl 3 · 0⤊ 0⤋
[Ne]3s²3p
2007-01-14 20:07:12 · answer #10 · answered by Curiously 5 · 0⤊ 0⤋