find the derivative of the following...1/(2-x)?

Question

please show all your work...i can't seem to get this one

Answer 1

Re-write it as:

(2 - x)ˉ¹

Now do it.

Does this help?

If not...how about now?

(2 - x)ª



:)

Answer 2

Assumption from the above situation is : f(x) = x^2 = x + x + x + x + ...... + x ( x circumstances ) Observations : a million) x^2 is a quadratic function - a non-end curve 2) x + x + x + ..... + x ( x circumstances ) - is a sum of linear equation. Argument : For (a million) : f(x) = x^2 f(a million) = a million f(2) = 4 f(3) = 9 . . . f(n) = n^2 while : From (2) : f(a million) = a million + a million + a million + .....+ a million ( x circumstances) f(a million) = x in addition, f(2) = 2x f(3) = 3x . . . f(n) = nx f(x) = x^2 needless to say, you will discover that the two are very diverse equations. notice that it is merely authentic at one factor x basically and not for all factors. And for spinoff to paintings, the curve must be non-end at each factor alongside the curve. So the fallacy that : f(x) = x^2 isn't equivalent to f(x) = x + x + x +x .....+ x for all values of x. for this reason, spinoff does not paintings right here. wish that explains.

Answer 3

1/(2-x)
dy/dx = [(2-x)*0 - 1*(-1)]/(2-x)^2
= -1/(2-x)^2

dy/dx = denominator tmes derivative of numerator - numerator times derivative of denominator, all divided by denominator^2.

Answer 4

f'(x) = (1'(2 - x) - 1(2 - x)')/((2 - x)^2)
f'(x) = (0(2 - x) - 1(1))/((2 - x)^2)
f'(x) = -1/((2 - x)^2)

Answer 5

Use the Chain Rule. The answer is going to be -ln(2-x) if im not mistaken...