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ozone is a poisonous of oxygen that in small concentrations is sometimes used to disinfect drinking water given the following equilibrium constatn explain why the formation of ozone in the air of your classroom not pose a health risk??

3O2 <=> 2O3 K= 1.6 * 10^-56 at 25 degrees

2007-01-14 11:10:19 · 3 answers · asked by peyman_m89 2 in Science & Mathematics Chemistry

3 answers

First, 25 degrees is room temperature.

Second, from definition of K,

1.6 * 10^-56 = [O3]^2 / [O2]^3

In other words, the ratio of ozone concnetration squared to oxygen concentration cubed is 1.6 * 10^-56.

Put in a dummy number for concentration of oxygen, say 1.

1.6 * 10^-56 = [O3]^2 / 1

1.6E-56 = [O3]^2 / 1

1.6E-56 = [O3]^2

[O3] = 1.26E-28

So the concentration of ozone is 1.26E-28 times the concentration of oxygen, in other words, close to nothing.

2007-01-14 11:21:57 · answer #1 · answered by Anonymous · 1 0

Since K=1.6X10^-56 and this equilibrium constant is equal to the concentration of ozone (which is a poisonous allotrope of oxygen) squared divided by the concentration of oxygen cubed, the value for the concentration of ozone must be vanishingly small at equilibrium. Simply stated, equilibrium expressions that have very small K values simply do not show much in the way of products.

2007-01-14 11:19:44 · answer #2 · answered by kentucky 6 · 0 0

Chlorine is nice because it has a unfavorable charge and numerous the contaminents in water are positivly charged. Chlorine is likewise surprising at killing residing organisms it truly is it regular function in ingesting water. many times if it were for a remedation type of function, activiated carbon will be used because of its capacity to soak up or bond with virtually some thing simply by 4 open spots on the electron valence.

2016-10-31 02:49:06 · answer #3 · answered by ? 4 · 0 0

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