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3. μ = 75, σ = 7.5, N = 10 α = .05 What values of (X bar) would lead to rejection of the null hypotheses if:
(a) the test was non directional
(b) if Ho stated that (X bar) ≤ μ and
(c) if Ho stated (X bar)  ≥ μ?

2007-01-14 11:08:54 · 3 answers · asked by NONE N 1 in Science & Mathematics Mathematics

3 answers

(a) You would reject the null if xbar is too large or too small. Since alpha is 0.05, then you would reject if |z| > 1.96, mean that either z > 1.96 or z < -1.96. Now

z = (xbar-mu)/(sigma/sqrt(n))
= (xbar-75)/sqrt(7.5/sqrt(10))

So set z to be either 1.96 or -1.96 to get your answer.

1.96 = (xbar-75)/sqrt(7.5/sqrt(10)) and solve for xbar.

Thus you would reject the null if xbar is larger than 79.649.

-1.96 = (xbar-75)/sqrt(7.5/sqrt(10))

You would also reject the null if xbar is smaller than 70.351.

(b). This time you would reject if xbar is too large. In terms of z, you would reject if z > 1.645 since alpha is 0.05. So use the same method as before.

1.645 = (xbar-75)/sqrt(7.5/sqrt(10)) and solve for xbar.

You would get 79.139. You would reject the null if xbar is larger than 79.139.

(c) Same as above, except this time you reject if xbar is too small. Use z = -1.645.

-1.645 = (xbar-75)/sqrt(7.5/sqrt(10)) and solve for xbar.

You would reject the null if xbar is less than 70.861.

2007-01-14 12:02:30 · answer #1 · answered by blahb31 6 · 1 0

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2016-12-16 04:45:14 · answer #2 · answered by Anonymous · 0 0

I think your null hypothesis in all cases is that m = 75

So in a) your alternative is m =/= 75, so it's a two tailed test

b) < means it's left tailed

c) > mean its right tailed.

2007-01-14 11:15:14 · answer #3 · answered by Modus Operandi 6 · 0 0

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