One type of antifreeze is 40% glycol, another type is 60% glycol. How much of each should be used to make 100 gallons of antifreeze that is 48% glycol? The answer I came up with is : 60 Gallons of the 40% and 40 Gallons of the 60% Is that correct?
2007-01-14 09:21:07 · 6 answers · asked by kkneisler 5 in Science & Mathematics ➔ Mathematics
let x = amount of 40 % glycol
Then 100-x = amount 0f 60 % glycol
.4x +.6(100-x) = 100(.48)
.4x +60 - .6x =48
-.2x = -12
x= 60 = gallons of 40% solution
100-x = 40 = gallons of 60% solution.
You are absolutely correct. Good work!
2007-01-14 09:31:25 · answer #1 · answered by ironduke8159 7 · 0⤊ 1⤋
The type of antifreeze you're describing is already premixed. Just add the 60% glycol to the radiator and you'll be OK.
The premixed is more expensive than 100 percent antifreeze. premix you're paying for 40 percent water. Purchase the 100 percent antifreeze and add water to it.
however if you are asking me to answer your school math problem , I won't do that.
2007-01-14 17:29:23 · answer #2 · answered by puppets48744 4 · 0⤊ 0⤋
yes one believes you are correct. well done
2007-01-14 17:31:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
0.4x+0.6y=48
4x+6y=480
x+y=100
4x+4y=400
subtracting
2y=80
y=40
substituting x=60
youranswer is correct
2007-01-14 17:27:32 · answer #4 · answered by raj 7 · 0⤊ 1⤋
your answer is correct
2007-01-14 17:32:22 · answer #5 · answered by michaell 6 · 0⤊ 0⤋
its easier to buy it from walmart
2007-01-14 17:25:22 · answer #6 · answered by booge 6 · 0⤊ 2⤋