when 0.860g of an organic compound contanining Carbon, Hydrogen, and Oxygen was burned completely in oxygen, 1.64 grams of carbon dioxide & 1.01 grams of water was produced. What is the empricial formula? Thanks for the help =)
2007-01-14 09:15:00 · 2 answers · asked by halomann4 1 in Science & Mathematics ➔ Chemistry
g=grams m=is 6*(10time10, 23 times=I cant write it !!) n=is the number of how many m do u have ....
now there is rules u need to know :- m*n=g
g/m=n
g/m=n
now 1.64 of carbon dioxide eas produced => that means g=1.64 M(CO2)= ( FROM THE TABLE OF THE ELEMeNTS) => 12+16*2=44 .... g/m=n 1.64/44=0.0372 mol
u do thw same thing with water ...
g=1.01 m=(from the table of elements) => 16+2*1= 18
G/M=n .. 1.01/18=0.0561 mol
HCO + O2 ====> 0.0372CO2 + 0.0561H2O
MHCO= g/m=n 0.0860/29=2.965mol
2007-01-14 10:07:31 · answer #1 · answered by AMP 2 · 0⤊ 0⤋
To put a simple perspective to this question, the burning of a hydrocarbon always produces CO2 and water. The balancing of the equation will enable you to know which hydrocarbon it is. Convert the grams in your problems to moles of CO2 and water. Now you can back calculate to determine the formula of the the starting hydrocarbon using the grams of the starting compund.
2007-01-14 18:17:50 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋