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please show me a tutorial of simplfing and solving the following rational
3x^5 *15xy two rational expressions
2y^3 9x^2 being divided then multiplied

(pretend theres a division line )

2007-01-14 07:39:11 · 2 answers · asked by kast5788 1 in Science & Mathematics Mathematics

2 answers

3 x^5*15 xy = 45 x^6 y (1)

and 2y^3*9x^2 = 18 x^2 y^3 (2)

1 and 2 share 3x^2y in common

(1) = 5 x^4 (9x^2y)

(2) = 2y (9x^2y) so dividing (1)/(2) = 5 x^4/2y

2007-01-14 07:57:56 · answer #1 · answered by maussy 7 · 0 0

( 3x^5 / 2y^3 ) * ( 15xy / 9x^2) =
( 3x^5 / 9x^2) * ( 15xy / 2y^3 ) =
( x^3 / 3 ) * ( 15x / 2y^2 ) =
( x^3 / 2y^2 ) * ( 15x / 3 ) =
( x^3 / 2y^2 ) * ( 5x / 1 ) =
( 5x^4 / 2y^2 )

or

( 3x^5 / 2y^3 ) * ( 15xy / 9x^2) =
(3*15 / 2*9) ((x*x^5) / (x^2))(y / y^3) =
(3*3*5 / 3*3*2) ((x^4) / 1)(1 / y^2) =
(5 / 2) (x^4 / 1)(1 / y^2) =
5x^4 / 2y^2

2007-01-14 08:13:12 · answer #2 · answered by Helmut 7 · 0 0

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