a.) decrease by a factor of 4
b.) remain the same
c.) increase by a factor of 2
d.) decrease by a factor of 2
e.) increase by a factor of 4
The answer is d.) decrease by a factor of 2, but I got a.) decrease by a factor of 4. What did I do wrong?
The equation you would use is F = (GM1M2) / r^2... right? (where G equals gravitational constant, and you know what the rest of the variables represent)
Help, please. ASAP.
2007-01-14 05:33:10 · 5 answers · asked by jhchiu2004 1 in Science & Mathematics ➔ Physics
you didn't go wrong - a is the answer - and you used the right formula - the r^2 makes it decrease by four instead of two
2007-01-14 06:03:41 · answer #1 · answered by Shellular Kellular 6 · 0⤊ 0⤋
a) decrease by a factor of 4 is correct, I think. The force should decrease by the distance squared (2^2=4). I can't say for sure, but I think whoever said d) is right was wrong.
2007-01-14 05:42:48 · answer #2 · answered by Onyx Blackman 3 · 1⤊ 0⤋
i ought to opt for D because earth and moon are actual revolving round a effortless centre of massfor a 2 body device. notwithstanding the centre of mass is so on the fringe of earth that it type of sounds like that in effortless words moon is revolving around the earth. apart from as for tidal pull :- its both way round and could stay the same way.(newton's 0.33 regulation). So comparable to earth the moon ought to have also confronted tidal pull(had there been water).So even after billion of years( if by some skill our planets live to inform the tale from solar's blowing up) issues will nonetheless be the same way.!!!!!!!!
2016-11-23 18:00:38 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Onyx got it right. The force is inversely proportional to the square of the distance. Twice the distance = 1/4 the force.
2007-01-14 06:55:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋
It's definitely a)
If it is a lame book, they might have made a mistake.
2007-01-14 06:04:59 · answer #5 · answered by Bushido The WaY of DA WaRRiOr 2 · 0⤊ 0⤋