Solve using the quadratic formula
1. x^2 + 6x + 4 = 0
2. Solve: 3x^2 = 75
2007-01-14 05:03:27 · 4 answers · asked by wil46yang 2 in Science & Mathematics ➔ Mathematics
Solving with the Quadtrtic Formula
x² + 6x + 4
a = 1,
b = 6
c = 4
x = - b ± √b² - 4ac / 2a
x = - 6 ± √(6)² - 4(1)(4) / 2(1)
x = - 6 ± √36 - 16 / 2
x = - 3 ± √20 / 2
x = - 3 ± 4.472135955 / 2
x = - 3 ± 2.236067978
- - - - - - - - - - -
Solving for +
x = - 3 + 2.236067978
x = 0.7639320023
- - - - - - - - -
solving for -
x - -2 - 2,236067978
x = - 5.236067978
- - - - - - -s-
2007-01-14 05:46:24 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
1. the quadratic formula is b +/- square root of (b^2- 4ac) then the total divided by 2a. in this case a=1 b=6 and c=4.... plug the numbers in
2. the same formula for this one a=3 b=0 and c= 0 or theres an easier way; divide both sides by 3 which leaves you with x^2= 25 which is equal to 5
2007-01-14 13:13:38 · answer #2 · answered by nrs_srn0001 1 · 0⤊ 0⤋
ok quadratic formula x = -b + or - radical (b^2 - 4ac) all over 2a
in the first one a = 1, b = 6, c = 4
in the second one a= 3 b = 0 c = -75
2007-01-14 13:06:43 · answer #3 · answered by michielev 2 · 0⤊ 0⤋
Um, I'm only in 8th grade pre-algebra and I have no clue what that quadratic formula is, but I would put together like terms and then subtract them on each side.... :-/
2007-01-14 13:08:38 · answer #4 · answered by sowhatperson 2 · 0⤊ 0⤋