2007-01-14 04:23:55 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
lwl - 2 = 1
lwl = 1 + 2
lwl = 3
w = 3 or -3
___________ _____________ _____________ ___________
-5 = lw-9l
Not solvable.
Since absolute value of any real number cannot be negative!
2007-01-14 04:28:19 · answer #1 · answered by Som™ 6 · 0⤊ 0⤋
The first:
lwl - 2 =1 move the two over
lwl = 3
w can equal 3, -3
The second:
lw-9l = -5 cannot be answered. The absolute value of anything cannot equal a negative number.
2007-01-14 12:30:38 · answer #2 · answered by monkey9 2 · 0⤊ 0⤋
Absolute value equations break down into two equations:
lwl - 2 = 1
becomes
w - 2 = 1
fiving
w = 3
and
-w - 2 = 1
giving
w = -3
Absolute value is always positive, so -5 = lw-9l is not permitted.
2007-01-14 12:43:44 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
In the first problem, treat it as an equation.
|w| - 2 = 1
|w| - 2 +2 = 1 + 2
|w| = 3
The absolute value of a number is the whole positive equivalent of that number. Thus, w = 3 or -3.
The second problem is unsolvable, because the absolute value of any number must be positive, and it shows a negative.
2007-01-14 12:30:33 · answer #4 · answered by baka_otaku30 5 · 0⤊ 0⤋