Solve the following system of linear inequalities by graphing.
x+y<5
0
I have the first one and the last one finished. The second one is the problem I am lost all I do know is the graph will have a solid line instead of dotted one.
I do have a okay graphing program but it will not help with this
So can anyone else?
The first answer that explains how or gives me a link to a example that will show me how gets best answer.
2007-01-14 03:45:29 · 6 answers · asked by bkm_71csi 3 in Science & Mathematics ➔ Mathematics
You shade in the section between horizontal section between y=0 and y=3. Both the lines, as you said, will have solid lines. it will take up three lines of boxes on your graph.
Y
/
bbbbbbbbbbbbbb/bbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbb/bbbbbbbbbbbbbbbbb
bbbbbbbbbbbbbb/bbbbbbbbbbbbbbbbb
============================
/
/
I tired to make a graph ahah the slashes are the y axis and the ='s are the x axis. The b's are what you should fill in with a solid line on top and bottm of the on 0, and 3.
(pretend the /'s are all lined up, when i try to submit it, it always moves back!)
2007-01-14 03:54:02 · answer #1 · answered by swimming♥ 2 · 1⤊ 0⤋
for the second graph, you get two different lines and end up shading in between.
since you have 0 < y < 3
it's the same as saying
y > 0
and
y < 3
you're going to have two horizontal lines.
one goes through the 3 and and another through 0 on the y-axis.
Since the numbers have to be greater than 0 but less than 3, you shade in between.
2007-01-14 11:55:29 · answer #2 · answered by OSO 3 · 1⤊ 0⤋
Since y is between 0 and 3, draw two horizontal dashed (dotted) lines, one through 0 on the y-axis (which ends up being the x-axis) and one through 3 on the y axis. Then shade in between.
It is dotted because you have < and not <=
2007-01-14 11:51:19 · answer #3 · answered by hayharbr 7 · 1⤊ 0⤋
ok. to graph the second one, rewrite it as two inequalities.
y>0 and
y<3
you graph two separate lines.
2007-01-14 11:50:02 · answer #4 · answered by yeayeawhatever 1 · 1⤊ 0⤋
The second one is a horizontal bar.
2007-01-14 11:49:39 · answer #5 · answered by modulo_function 7 · 1⤊ 0⤋
0
number line
y = 0(_______________)3
Cartesian
<- - - - - - - - -3|- - - - - - - - ->
:::::::::::::::::::::::|:::::::::::::::::::::::
:::::::::::::::::::::::|:::::::::::::::::::::::
:::::::::::::::::::::::|:::::::::::::::::::::::
:::::::::::::::::::::::|:::::::::::::::::::::::
<- - - - - - - - -0|- - - - - - - - ->
2007-01-14 12:16:45 · answer #6 · answered by Anonymous · 1⤊ 0⤋