Area is zero, since 50 > 20 + 25. Can't form a triangle with those sides. However if you misheard this one, and it's really 20, 25, and 15 inches, that forms a right triangle of proportions 3, 4, 5, and the area of this triangle would be 1/2 (15)(20), or 150 square inches.
2007-01-14 02:32:32
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answer #1
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answered by Scythian1950 7
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The area of a triangle is equal to 1/2 * BASE*HEIGHT.
1/2bh
But since 20 and 25 is equal to 45 you must have measured wrong because you triangle table, would have to be a straight line.
2007-01-14 03:46:45
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answer #2
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answered by swimming♥ 2
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Urm, I hate to tell you this dude, but I think it's impossible to have a triangle table that way...
If the sides are 20:25:50 inches,
then the ratio would be 4:5:10 inches.
If you don't believe me, you can try plotting the triangle of the above ratio in cm in a graph paper....
It's... Impossible...
2007-01-14 02:37:59
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answer #3
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answered by sheepishbiribiri 2
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Those three lengths can't form a triangle. This is obvious: no mater how wide you open up one side of 20 and another of 25, the longest third-side they could make would approach 45.
2007-01-14 02:34:03
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answer #4
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answered by TimmyD 3
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Impossible, the longer side is too big. Should be less than the sum of the 2 smaller ones.
2007-01-14 02:33:33
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answer #5
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answered by gianlino 7
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Cannot form a triangular table of those dimensions on this planet. Sorry.
2007-01-14 02:51:38
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answer #6
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answered by Anonymous
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my math's a lil rusty but if im not wrong,
using cosine rule, u can find one of the 3 angles, i found the one angle between 20 and 25, and it's 137.5 degrees,
then, use the sine rule [1/2xAxBxsinc] and u'll get area to be 168.9 inches squared.
ps correct me if im wrong.
rgds
2007-01-14 02:39:36
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answer #7
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answered by samseventy2 2
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hey itz quite impossible, throw away ur imaginary triangle table.
2007-01-14 02:53:02
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answer #8
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answered by Roopa R 3
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