2007-01-14 00:39:53 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
You would get full combustion of the methane to give carbon dioxide and water. If the ammount of oygen was restricted you can get incomplete combustion giving carbon monoxide or carbon (soot) instead of carbon dioxide
2007-01-14 01:39:28 · answer #1 · answered by Gordon B 7 · 0⤊ 0⤋
You have two products - Carbon dioxide an Water.
CH4 + 2O2 = CO2 + 2H2O
Methane + Oxygen = Carbon Dioxide + Water
The molar ratios are :-
1 : 2 :: 1 : 2
2007-01-16 08:25:37 · answer #2 · answered by lenpol7 7 · 0⤊ 0⤋
You have a classic combustion reaction. The products of a combustion with excess oxygen are always water vapor and carbon dioxide.
CH4 + 2 O2---> 2 H2O + CO2
2007-01-14 00:43:50 · answer #3 · answered by wizzardx3 2 · 0⤊ 0⤋
You will get Carbon Dioxide, Water vapour, Unused Oxygen and Heat.
2007-01-17 10:03:56 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋
It burns with a blue flame i.e. complete combustion.
Carbon dioxide and water vapour are released.
2007-01-14 02:26:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
With excess of oxygen, you will produce carbon dioxide, and water, with plenty of heat. There should be no carbon monoxide, and no unburned carbon.
2007-01-14 00:47:42 · answer #6 · answered by sparbles 5 · 0⤊ 0⤋
the reaction will only use as much oxygen as it would normally.. irrespective whether there is a higher level of oxygen in the air or not
2007-01-14 00:42:38 · answer #7 · answered by Danny F 2 · 0⤊ 0⤋
CH4 + 2O2 --------> 2H2O + CO2
you will get water and carbon dioxide.
2007-01-14 00:45:16 · answer #8 · answered by Anonymous · 0⤊ 0⤋
CH4 + 2O2 --> CO2 + 2H2O
2007-01-14 02:31:19 · answer #9 · answered by Kemmy 6 · 0⤊ 0⤋