How much times does the wind blow harder at 140 MPH than 100?

Question

Not 1.4x

Answer 1

Well, if you are asking with respect to the energy levels in the wind, you will have to use the formula Kinectic Energy(K.E.)=0.5 m v^2.

The energy exerted by the wind at 140MPH/225.30816KMPH will be 25381.8824mN, where m represents the mass of the air particle moving, and N being the unit of energy.

Assuming that the same air particle is now moving at 100MPH/160.9344KMPH, the energy exerted by the wind will be 12949.9405mN.

Taking into account that the m in both scenarios are the same, the wind at 140MPH is 1.959999924 times stronger that the wind at 100MPH

Answer 2

It's not the energy, but the force that counts!

The force that a flowing fluid (including gases) exerts on a body is hard to calculate because it depends on many factors, but a simple model can help us answer this question:

The force is equal to the passed momentum in unit time. The momentum is passed mass times the velocity. The mass is density times passed volume. The passed volume is cross - sectional area time distance traveled. The distance traveled in unit time is velocity, so the formula gives:

F = d A v^2

Nevermind d and A, F is proportional to v^2, so:

F2/F1 = (v2/v1)^2 = (140/100)^2 = 1.4^2 = 2.0 (you should use two significant figures!)

Doing a similar argument on the transimited energy in unit time (Power) we arrive at:

P = d A v^3 / 2, or P is proportional to v^3!

Answer 3

energy is proportional to the speed squared so thenenergy at 140 mph is (140/100)^2=1.96 times as high.