factor this pls x^2-y^2+x+y?

Question

x^2-y^2+x+y

Answer 1

since x² - y² = (x - y)(x + y) so

x² - y² + x + y = (x - y)(x + y) + (x + y) =
x² - y² + x + y = (x + y) [ (x - y) + 1]

Answer 2

x^2 - y^2 + x + y
= (x - y +1)( x +y)

Answer 3

(x^2 - y^2)+(x+y)
= (x-y)(x+y) + (x+y)
= (x+y)(x-y+1)

Answer 4

To factor this, you have to use grouping. Factor the first two terms and the last.

x^2 - y^2 + x + y

(x - y)(x + y) + x + y

It may not be immediately obvious that it groups, so I'll make it obvious by doing this:

(x - y) (x + y) + (1)(x + y)

Each term has an (x + y), so we factor that out of the whole thing.

(x + y) (x - y + 1)

Answer 5

x² - y² +x + y =

(x + y)(x - y + 1)

- - - - - - -s-

Answer 6

(x²-y²)+(x+y) = (x-y)(x+y)+(x+y)
= (x+y)(x-y+1)

Answer 7

Given exp=(x^2-y^2)+(x+y)
=(x+y)(x-y)+(x+y)
=9x=y) (x-y+1)
t

Answer 8

x^2-y^2 is in the form of [a^2-b^2=(a+b)(a-b)]
let a=x and be=y
it becomes
(x+y)(x-y)(x+y)
take (x+y) common
this becomes
(x+y){(x-y)+1}

Answer 9

(x + y)(x - y) + (x + y)

now factor (x + y)

(x + y)[(x - y) + 1]