The graph 5x2quare shifted units to the right and 8 units belw the axis?? I dont get it.. LOL
2007-01-13 18:52:20 · 3 answers · asked by Andie 2 in Science & Mathematics ➔ Mathematics
according to the theorem
f(x) = a(b(x - c))^2 + d
assume
f(x) = 5x^2
shifted some# units to the right
f(x) = 5(x - #)^2
8 units down
f(x) = 5(x - #)^2 - 8
2007-01-13 19:23:28 · answer #1 · answered by ? 2 · 0⤊ 0⤋
I don't get it, either. Presumably you have y = 5x^2 , but how many units to the right do you want to move it?
Your new equation will be (y + 8) = 5(x - a)^2, where a is the number of units you want to move right.
2007-01-14 03:06:35 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
it will be a parobola, opening upward, with the minimum being at the point (units to the right, -8); you didn't say how many units to the right it should be shifted though.
2007-01-14 03:02:13 · answer #3 · answered by Voodoo6969_98 2 · 0⤊ 0⤋