How do u solve these equations?

Question

x-3=x+2
3x=x+3
6+x=8-2x
7x=3-x+3x-2
x-3x+5=4+x


and the quadratics
x^2+x=4x^2+4
x+8x^2=81+x^2+3x


thanks!!!

Answer 1

1. x-3=x+2
<=> 0x - 3 = 2 <=> no x is the root of this equation
2. 3x=x+3
<=> 2x = 3 <=> x = 3/2
3. 6+x=8-2x
<=> 3x = 2 <=> x = 2/3
4. 7x=3-x+3x-2
<=> 5x = 1 <=> x = 1/5
5. x-3x+5=4+x
<=> 3x = 1 <=> x = 1/3


6. x^2+x=4x^2+4
<=> 3x^2 - x + 4 = 0
delta = 1 - 3*4*4 < 0
thus this equation has no real root
7. x+8x^2=81+x^2+3x
<=> 7x^2 - 2x - 81 = 0
delta = 4 + 4*7*81 = 2272
sqrt(delta) = 4*sqrt(142)
x = (1 + 2sqrt(142)) / 7
or x = (1 - 2sqrt(142)) / 7

Answer 2

x-3=x+2-- no answer - change it to x - x = 5, which is 0 = 5, and that's not a true statement
3x=x+3 -- make it 2x = 3, and then x = 3/2 or 1.5
6+x=8-2x -- make it 3x = 2, which makes it x = 2/3 or about 0.667
7x=3-x+3x-2 -- that's 7x = 1 + 2x, which is 5x = 1. so x = 1/5 or 0.2
x-3x+5=4+x-- that's -2x + 5 = 4 + x, which is 1 = 3x, so x = 1/3 or about 0.333

x^2+x=4x^2+4
make it all equal to zero: 0 = 3x^2 - x + 4
it looks unfactorable to me, so do the quadratic formula, and you get:
x = 0.16666666666666666 plus or minus 1.1426091000668406(i)

x+8x^2=81+x^2+3x
set to zero: 0 = 7x^2 - 2x - 81
also unfactorable
so quadratic equation again, and your two possible x values are:
x = 3.5475357965179954, and x = -3.26182151080371

Answer 3

x - 3 = x + 2 is not solvable

3x = x+3 => 2x = 3 => x = 3/2

6 + x = 8 - 2x => 3x = 2 => x = 2/3

7x = 3 -x + 3x - 2 => 5x = 1 => x=1/5

x - 3x + 5 = 4 + x => 3x = 1 => x=1/3

3x^2 - x - 4=0
x^2 - 1/3 x - 4/3 = 0
x^2 - 1/3x + (1/6)^2 - (1/6)^2 - 4/3 = 0
(x - 1/6)^2 - (1/36 + 4/3) = 0
(x- 1/6)^2 - (49/36) = 0
(x - 1/6 - 7/6)(x - 1/6 + 7/6) = 0
(x - 4/3)(x + 1) = 0
x=4/3
x= - 1

7x^2 - 2x -81 = 0
x^2 - 2/7x -81/7 = 0
x^2 - 2/7x + (1/7)^2 - (1/7)^2 - 81/7 = 0
(x - 1/7)^2 - (1/49 + 567/49) = 0
(x - 1/7 - sqrt(568)/7)(x - 1/7 + sqrt(568)/7) = 0
x = (1 + sqrt(568))/7
x = (1 - sqrt(568))/7

yw

Answer 4

x-3=x+2
Add 3 to both sides: x=x+5
Subtract x from both sides: 0=5

3x=x+3
Subtract x from both sides: 2x=3
Divide both sides by 2: x=3/2

6+x=8-2x
x=2-2x
3x=2
x=3/2

7x=3-x-3x-2
7x=1-4x
11x=1
x=1/11

x-3x+5=4+x
-2x+5=4+x
-2x=-1+x
-3x=-1
x=1/3

Answer 5

this would seem complicated, notwithstanding it truly is definitely extremely undemanding. i visit do quantity 2 for you because that is the hardest. 2(6x+3)=3(2x+12) a million. you want to distribute both and the three. this provides you: 12x+6=6x+36 2. Now you want to get "x" to one fringe of the equation and the each thing else to the different. Subtract 6x from each and each facet. You get: 6x+6=36 once it really is done, you want to subtract the "6" from each and each facet. 6x=36 3. Now you want to sparkling up for "x" by technique of dividing each and each facet by technique of 6. this provides you "x'' on one facet. 36 divided by technique of 6 = 6 the answer is x=6 question a million is x=-3 question 2 is x=6 question 3 is x=-3 desire that made experience !

Answer 6

C'mon!!!!! What grade are you in???