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50x= -75y+ 65

I converted the equation to slope-intercept, and plugged in some points into the point-slope form, and ended up with: y- 13/5= 50(x-0), but it doesn't look right.

2007-01-13 17:12:45 · 5 answers · asked by lirael1019 1 in Science & Mathematics Mathematics

5 answers

*Set the equation in the slope-intercept form > y = mx + b

First: add 75y to both sides...

50x + 75y = -75y + 75y + 65
50x + 75y = 65

*Subtract 50x from both sides...

50x - 50x + 75y = -50x + 65
75y = -50x + 65

*Divide everything by 75...

75y/75 = (-50/75)x + 65/75
y = (-50/75)x + 65/75
y = -(2/3)x + 13/15

The slope is a fraction/number beside the "x" which is, -2/3...
*At this point, there is nothing left to do because you didn't provide us with a point (x, y)...please check your book to write the problem correctly.

2007-01-14 04:53:56 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 0

It's not. You need 2 things, slope and a point on the line. Slope here is 50/-75 = -2/3. An easy point has y = 0, x = 65/50 = 13/10. So one form of the equation is

y - 0 = (-2/3)(x - 13/10)

2007-01-14 01:23:08 · answer #2 · answered by Philo 7 · 0 0

move y to the other side
y = -50/75 x + 65/75
y = -2/3 x + 13/15

the slope is -2/3

2007-01-14 01:29:20 · answer #3 · answered by Anonymous · 1 0

move the constant from the left to the right. You're close, but I'd say first divide by 75; your constant for the slope is wrong. it should be 2/3 or -2/3.

2007-01-14 01:18:00 · answer #4 · answered by John 4 · 0 0

Do you have the two point sets for this problem. You need to provide more to this question before I can help you out!

2007-01-14 01:19:17 · answer #5 · answered by Anonymous · 0 0

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