algebra length triangle?

Question

The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the lenght of the base. if the perimeter is 29cm, find the lenght of one of the equal legs.

thanks

Answer 1

Let x = length of base
Then one leg = 4x-8
So perimeter = x + 4x-8 +4x-8 = 29
9x -16 = 29
9x = 45
x=5
4x-8 = 20-8 =12 = length of one of the equal sides

Answer 2

The wall on which the ladder is positioned makes a ninety perspective with the floor, so that you'll be able to keep on with Pythagoras' Theorem (c^2 = a^2 + b^2, the position c is the hypothenuse). thus, the ladder of length 12 feet is c. enable b = y, and a = x. Transpose the equation to style... b^2 = c^2 - a^2 even as x = a million, y = *squareroot* (12^2 - a million^2) = *squareroot* 143 ft even as x = 3, y = *squareroot* (12^2 - 3^2) = 3 *squareroot* 15 ft even as x = 6, y = *squareroot* (12^2 - 6^2) = 6 *squareroot* 3 ft even as x = 8, y = *squareroot* (12^2 - 8^2) = 4 *squareroot* 5 ft P.S. Drawing a diagram can assist fairly. ;)

Answer 3

Perimeter= 2L + B
L = 4B - 8
so 2(4B - 8) + B = 29
9B - 16 = 29
9B = 45 so B = 5 cm
and L = 12 cm

Answer 4

The answer is 12.
The length of base is 5 and the legs are both 12.

Answer 5

8.3(app) see how... as you told the equal side measure 8 cm less than 4 times the base. So if the base i s "x" then measure of each equal side should be 4x-8. Right? so now the perimeter should be 4x-8 + 4x-8+X=29. I hope you got it now

Answer 6

x=the length of one leg
4x-8=the length of the base

x+4x-8+4x-8=29
9x-16=29
9x=45
x=5

4(5)-8
20-8=12

It's 12 cm.

Answer 7

l=4b-8
p=29=2l+b
29=2(4b-8)+b
29=8b-16+b
45=9b
b=5
l=4b-8=4*5-8=20-8=12
the legs are 12 cm

Answer 8

4y-8=x
2x+y=29
x=12
y=5
answer, 12 cm.