solve using quadratic formula?

Question

. Solve using the quadratic formula:
x2 – 2x = 5x – 2

Answer 1

x^2 -7x +2 = 0
Now you have everything you need to solve the equation.

Okay, I'll even give you a way to cheat (besides asking someone else to solve it for you): http://www.math.com/students/calculators/source/quadratic.htm

Answer 2

Question Number 1 : For this equation x^2 - 7*x - 1 = - 7 , answer the following questions : A. Find the roots using Quadratic Formula ! B. Use factorization to find the root of the equation ! C. Use completing the square to find the root of the equation ! Answer Number 1 : First, we have to turn equation : x^2 - 7*x - 1 = - 7 , into a*x^2+b*x+c=0 form. x^2 - 7*x - 1 = - 7 , move everything in the right hand side, to the left hand side of the equation <=> x^2 - 7*x - 1 - ( - 7 ) = 0 , which is the same with <=> x^2 - 7*x - 1 + ( 7 ) =0 , now open the bracket and we get <=> x^2 - 7*x + 6 = 0 The equation x^2 - 7*x + 6 = 0 is already in a*x^2+b*x+c=0 form. In that form, we can easily derive that the value of a = 1, b = -7, c = 6. 1A. Find the roots using Quadratic Formula ! Use the formula, x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a) We had know that a = 1, b = -7 and c = 6, we need to subtitute a,b,c in the abc formula, with thos values. Which produce x1 = (-(-7) + sqrt( (-7)^2 - 4 * (1)*(6)))/(2*1) and x2 = (-(-7) - sqrt( (-7)^2 - 4 * (1)*(6)))/(2*1) Which is the same with x1 = ( 7 + sqrt( 49-24))/(2) and x2 = ( 7 - sqrt( 49-24))/(2) Which make x1 = ( 7 + sqrt( 25))/(2) and x2 = ( 7 - sqrt( 25))/(2) So we get x1 = ( 7 + 5 )/(2) and x2 = ( 7 - 5 )/(2) So we have the answers x1 = 6 and x2 = 1 1B. Use factorization to find the root of the equation ! x^2 - 7*x + 6 = 0 ( x - 6 ) * ( x - 1 ) = 0 The answers are x1 = 6 and x2 = 1 1C. Use completing the square to find the root of the equation ! x^2 - 7*x + 6 = 0 ,divide both side with 1 Then we get x^2 - 7*x + 6 = 0 , We know that the coefficient of x is -7 We have to use the fact that ( x + q )^2 = x^2 + 2*q*x + q^2 , and assume that q = -7/2 = -3.5 So we have make the equation into x^2 - 7*x + 12.25 - 6.25 = 0 Which can be turned into ( x - 3.5 )^2 - 6.25 = 0 So we will get (( x - 3.5 ) - 2.5 ) * (( x - 3.5 ) + 2.5 ) = 0 By using the associative law we get ( x - 3.5 - 2.5 ) * ( x - 3.5 + 2.5 ) = 0 And it is the same with ( x - 6 ) * ( x - 1 ) = 0 So we got the answers as x1 = 6 and x2 = 1

Answer 3

Write in standard form: x² - 7x + 2 = 0
a = 1, b = -7, c = 2, so

x = 7/2 ± √(49 + 4) / 2
x = 7/2 ± (1/2)√53

Answer 4

Its easy, but before I start, I want to tell that I have considered that x2 implies x^2 and not 2x cause that doesnt make sense.

Given,
x2 - 2x = 5x - 2
=> x2 - 7x + 2 = 0 ( Taking all the left terms into the right side)
Now, we cant find two integers that give -7 on addition and 2 on multiplication of the same.Hence, we use the following formula.

x1 = [-b + sqrt(b^2 - 4ac)]/2a
x2 = [-b - sqrt(b^2 - 4ac)]/2a ( Yo, yo, here x2 implies x2 itself and not x^2. Its the second root)

where b= -7 , c=2 , a=1

x1 = [7 + sqrt(49 - 4(1)(2)]/2
=> x1 = [7 + sqrt(41)]/2

similarly, x2 = [7 - sqrt(41)]/2

therefore, x1 = [7 + 6.4031]/2 = 6.7015
x2 = [7 - 6.4031]/2 = 0.2984

x1 = 6.7015
x2 = 0.2984

Peace out.

Answer 5

mostly all quadratic formula when you solve it and get the answer you can divided it so that you can get a whole number so my point is that theres a mistake in the equation because when i solve it i got decimal point.

Answer 6

x^2-7x+2=0

The quadratic formula:
x=-b±√b^2-4ac/2a
a=1,b=-7,c=2
x=(7±√49-8)/2
x=(7±√41)/2

Answer 7

The only thing I can do on here is give you the two answers.
If you want to see the solution, email me at
[e-mail]
I'll work it out on paper and email back the solution by scanning and adding it as an attachment. - kevin