i know csct= 1/sint and sect= 1/cost. dont know where to go from there.
2007-01-13 15:10:00 · 4 answers · asked by k j 1 in Science & Mathematics ➔ Mathematics
cos (90-t) = sin t
sin (90 - t) = cos t
sin t / csc t = sin t / (1/sin t) = sin^2 t
etc
2007-01-13 15:25:04 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
cos(90*-t)/csct + sin(90*-t)/sect
= sin^2 t + cos^2 t
= 1
Reasons: cos(90-t) = sint, 1/csct = sint; sin(90-t) = cost, 1/sect = cost
2007-01-13 23:23:03 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
simplify cos(90*-t)/csct + sin(90*-t)/sect
cos(90-t) = sint and sin (90-t) = cost
sint/csct + cost/sect
sint/(1/sint) + cost/(1/cost
sin^2t+cos^2t = 1
2007-01-13 23:27:13 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
cos (90-t) = sin t
sin (90 - t) = cos t
sin t / csc t = sin t / (1/sin t) = sin^2 t
2007-01-17 22:04:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋