I suppose I have to solve this: I don't know where to start
v=3k+5d solve for d
This is what I have
3K=5d=v
3k+5d-3k=v-3k
5d=v-3k
5d/5=v-3k/5
d= v-3k/5
Is this correct?
2007-01-13 14:33:10 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
v = 3k + 5d
Moving the 3k to the left hand side, it becomes -3k, so we have
v - 3k = 5d
Now, let's divide both sides by 5.
(v - 3k)/5 = d
The only correction (though it's only a syntax error on here and probably looks crystal clear on paper) is the brackets around
(v - 3k)/5. When you write it like that, it's ambiguous, because it can either mean
v - (3k/5) OR
(v - 3k)/5
2007-01-13 14:40:26 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
That is correct your answer.
v=3k+5d
v - 3k = 5d
(v - 3k) : 5 = d
d = v/5 - 3k/5
<>
2007-01-13 22:40:08 · answer #2 · answered by aeiou 7 · 1⤊ 0⤋
Not quite.
You need to put paretheses around v-k, so
d = (v-3k)/5
v - 3k/5 is qyuite different from (v-3)/5.
Use parentheses whenever there is a possibility your true meaning can be misinterpreted.
2007-01-13 22:46:04 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
Your work should look like this:
v=3k+5d solve for d
5d=v-3k
d=(v-3k)/5
Mind the parenthesis.
2007-01-13 22:42:45 · answer #4 · answered by smittodchess 1 · 1⤊ 0⤋
v=3k+5d
Subtract 3k from both sides:
v-3k=5d
Divide 5 from both sides:
d=(v-3k)/5
This is correct!
2007-01-14 00:39:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
no,it isn't.
d=v/5-3k/5 or d=1/5(v-3k)
2007-01-13 22:55:39 · answer #6 · answered by Johnny 2 · 0⤊ 2⤋
yes
2007-01-13 22:36:19 · answer #7 · answered by Blake 1 · 2⤊ 0⤋