I need to solve for v
D=vt-1/2at^2
vt-1/2at^2=D
2(vt-1/2at^2)=(2)D
2vt-at^2+at^2=2D+at^2
2vt/st=2d/2t+at^2/2t
v=d/t+at/2
v=d/t+1/2at
Is this correct..
2007-01-13 14:31:29 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'll solve it too and we can compare.
D = vt - (1/2) (a) (t^2)
Moving the second term on the right hand side to the left hand side, we have
D + (1/2) (a) (t^2) = vt
To get rid of that fraction, let's multiply everything by 2.
2D + a(t^2) = 2vt
Now, let's divide both sides by 2t.
(2D + at^2)/(2t) = v
This can be changed to two fractions:
v = 2D/(2t) + (at^2)/(2t)
v = D/t + (1/2)at
2007-01-13 14:36:06 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
Correct, I have it here in two steps:
vt = (1/2)at^2 + D, added (1/2)at^2 to both sides
v = (1/2)at + D/t, divided through by t
2007-01-13 22:36:44 · answer #2 · answered by Action 4 · 0⤊ 0⤋
yes
2007-01-13 22:35:23 · answer #3 · answered by Blake 1 · 0⤊ 0⤋
yes ma'am
2007-01-13 22:35:58 · answer #4 · answered by katie 3 · 0⤊ 0⤋
YEP, YOU GOT IT.
2007-01-13 22:37:11 · answer #5 · answered by 7 · 0⤊ 0⤋