2007-01-13 13:47:45 · 4 answers · asked by Hiawatha 2 in Science & Mathematics ➔ Chemistry
3.68E30 carbon atoms / 6.0221415 E23 atoms/mol = 6110783.016 mol C
6110783.016 mol C * (1 mol C6H12O6) / (6 mol C) = 1018463.836 mol C6H12O6
1 mol C6H12O6 = 6*12+12*1+6*16=180 g C6H12O6
1018463.836 mol C6H12O6 * (180 g C6H12O6 / mol C6H12O6) = 5658.132423 g C6H12O6
2007-01-13 13:57:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You need to use avogadro's # and the molecular mass of glucose. Each molecule of glucose has 6 carbon atoms.
3.68 X 10E30 / 6 = 6.13 X 10E29 molecules / 6.02 X 10E23 =
1.01 X10E6 moles of glucose.
MM of glucose is 180 grams / mole.
So you need 1.8 X 10E8 grams of glucose.
2007-01-13 14:02:13 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
42
2007-01-13 13:53:51 · answer #3 · answered by MiKe Drazen 4 · 0⤊ 0⤋
I'll post a comment because there are 3 different answers here... but I agree with Nick C. That is the correct answer.
2007-01-13 15:23:05 · answer #4 · answered by Xenon 3 · 0⤊ 0⤋