Combine into one fraction: 3/4x^2y + 5/7x^3y^2?

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2007-01-13 13:08:52 · 3 answers · asked by Ethan S 2 in Science & Mathematics ➔ Mathematics

3/ 4x^2y + 5 / 7x^3y^2

3xy/ 4x^3y^2 + 5 / 7x^3y^2

21xy/ 28x^3y^2 + 20 / 28x^3y^2

( 21xy + 20)/ 28x^3y^2

2007-01-13 13:12:27 · answer #1 · answered by Anonymous · 1⤊ 0⤋

3/ 4x^2y + 5 / 7x^3y^2

Cross multiply the denoms with the nums.

[21x^3y^2 + 20x^2y ] / 28x^6y^3

Take out x^2y from both:

[21xy + 20] / 28x^3y^2

2007-01-13 21:38:25 · answer #2 · answered by Stryder 2 · 0⤊ 0⤋

If you read it as (3/(4x^2y)) +5/(7x^3*y^2) the answer is

(21*x^3*y^2+20x^2y)/(28* x^(3+2y)*y^2)
really it doesnÂ´t make sense to me

2007-01-13 21:35:37 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋