Don't solve it for me, just what is it in the formula?
2007-01-13 08:56:19 · 8 answers · asked by girl_pink 1 in Science & Mathematics ➔ Mathematics
3 +/- [sqrt ((-3)^2 -(4(2)(5))]/2(2)
2007-01-13 09:02:17 · answer #1 · answered by Anonymous · 0⤊ 2⤋
2x^2 - 3x + 5 = 0 is the quadradratic equation.
a=2
b= -3
c=5
the quadratic formula: ( -b plus or minus [sqrt (b^2 - 2ac)] ) / 2a
plug in the numbers for a b and c
2007-01-13 17:02:41 · answer #2 · answered by :) 3 · 2⤊ 0⤋
The formula is x = [-b +or- (b^2-4ac)^1/2]/2a
a is the coefficent of x^2, b, the coefficient of x and c = constant
in your ex a = 2 b= -3 and c= 7
2007-01-13 17:25:05 · answer #3 · answered by 1ofSelby's 6 · 1⤊ 0⤋
2x^2-3x+5=0
Here's the formula:
x=-b屉b^2-4ac/2a
a=2,b=-3,c=5
I hope this helps and good luck with your assignment!
2007-01-14 01:03:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x^2-3x+5=0
Basically i subtracted the 3x and made it equal to zero.
2007-01-13 17:03:43 · answer #5 · answered by musicfanlh 2 · 2⤊ 1⤋
a=2
b=-3
c=5
[3 +/- (9-4*2*5)^1/2] / 4
2007-01-13 17:00:44 · answer #6 · answered by mom 7 · 0⤊ 2⤋
a = 2
b = -3
c = 5
2007-01-13 16:59:19 · answer #7 · answered by mlw1235 2 · 1⤊ 1⤋
2X^2-3X+5
2007-01-13 17:00:13 · answer #8 · answered by Anonymous · 1⤊ 1⤋