Whose equation is that X2+Y2 = Z2?

Answer 1

Pythagoras

Answer 2

The equation "belongs" to many mathematicians.

It has already been answered that Pythagoras of Samos (580-500 BC) used it to find the hypothenuse (diagonal) of a right-angle triangle (actually, his feat was in proving why the equation worked).

If the equation is to be resolved using only integers, then it is called a Diophantine equation (Diophantus, a Greek mathematician around 250 BC).

There was a whole series and the problem was to determine if the equation: X^n + Y^n = Z^n had any non-zero integer solution when n was an integer greater than 2 (Thanks to Pythagoras, n=2 was already solved).

Then along came Fermat (look up Fermat's last theorem in Wikipedia) who wrote, in the margin of a friend's book that explained the Diophantine problem:

"Cuius rei demonstrationem mirabilem sane detexi. Hanc marginis exiguitas non caperet."

(I have a truly marvelous proof of this proposition which this margin is too narrow to contain.)

So, the equation is also associated with Pierre de Fermat (French lawyer and mathematician, 1608-1665)

Answer 3

I think I've got the question deciphered...

"Whose theorem states that A^2 + B^2 = C^2?"

Answer = Pythagoras

The equation 2x + 2y = 2z is nothing more than an equation.

Answer 4

Its a equation of circle , whose center is at the origin(0,0)

The general equation of circle having center at (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2

if ( h,k) = (0,0)
then the equation becomes

x^2 + y^2 = r^2

Answer 5

It is the equation of a circle with the radium 1.

Answer 6

It's a Pythagorean Theorem.

Answer 7

unless you mean
x^2 + y^2 = z^2
that's the pythagorean theorem
but it usually uses a b and c

Answer 8

It is the equation of a circle where Z is the radius of the circle

Answer 9

It is the equation of a circle

Answer 10

It was first discovered by BHASKARUDU-2 of India.
But he didi not prove it
Pythagoras proved it
So he gets the credit