There are 12 guests at Andy's party. He has prepared 12 sealed envelopes, two of which contain $5 bills, and will allow each guest to pick an envelope.
Will Bess have a better chance of winning $5 if she picks first or if she picks seventh, with another guest already having won $5?
a. If she picks first
b. If she picks seventh, with one winner already
c. Equal chance
2007-01-13 03:37:05 · 7 answers · asked by Hardcore 3 in Science & Mathematics ➔ Mathematics
c
2007-01-13 03:46:00 · answer #1 · answered by srinu710 4 · 1⤊ 0⤋
C = equal
Picking first is 2 out of 12 = 1/6
Picking seventh means six people already picked, and 6 to go, so it's 1 out of 6 = 1/6
2007-01-13 11:40:54 · answer #2 · answered by ecolink 7 · 2⤊ 0⤋
a. If she picks first.
she has a 2/12 (or 17%) chance in getting the $5
b. If she picks seventh, with one winner already
she has 1/6 (or 17%) chance in getting the $5
c. equal chance
Whatever the first person said.
You tell me. Which one sounds more likely?
2007-01-13 11:44:21 · answer #3 · answered by jubbablumberin 3 · 1⤊ 0⤋
the probability of pickinig the winning envolope is equal to the number of winning envlope divided by the number of empty ones
so
1) if she picks first:
probabilty of winning =2/12
= 1/6
2) if she picked seventh( note that there is only 6 envolopes left and only 1 winning envlope)
probabilty of winning = (2-1)/(12-6)
= 1/6
so the answer to your question will be no. c
2007-01-13 11:47:50 · answer #4 · answered by HuMaN being 2 · 1⤊ 0⤋
C. Equal chance
2007-01-13 11:48:17 · answer #5 · answered by abnatra 2 · 2⤊ 0⤋
b
2007-01-13 12:04:17 · answer #6 · answered by anty93 2 · 0⤊ 1⤋
Errrrr, I dunno..? i'm to dumb to answer.. I'll say either D or K, but i'm going with D.
2007-01-16 02:21:02 · answer #7 · answered by Mike J 1 · 0⤊ 0⤋