factor the expression x^3+8y^3?

Answer 1

Sorry, but if I do your homework for you then you'll learn nothing.

Answer 2

factor by applying looking something uncomplicated in the two aspects of the expression x(3) + 8y(3) 3(x+8y) now no rely if that's a cube then that's an entire nother ball of wax. DO YOU propose IT AS IS OR AS CUBED?

Answer 3

x^3 + 8y^3 = (x+ay)(x^2 + bxy + cy^2)
x^3 + 8y^3 = x^3 +(a+b)x^2y + (ab+c)xy^2 + acy^3

a+b = 0
b=-a

ab + c = 0
a(-a) + c = 0
-a^2 +c = 0
a^2 = c

ac=8
a(a^2)=8
a^3 = 8

So, a = 2, b=-2, c = 4
x^3 + 8y^3 = (x+2y)(x^2 -2xy + 4y^2)
As x^2 -2xy + 4y^2 cannot be factored in real number,

x^3 + 8y^3 = (x+2y)(x - y(1+ sqrt(3)i))(x - y(1 - sqrt(3)i))

Answer 4

hint: it's the "sum of two cubes"
[ NOTE 8y^3 = (2y)^3 ]


X ^3+ Y^ 3 = (x + y)(X^ 2 - XY + Y ^2 ) <== "general 'form' " and NOT the "answer" buta good clue to HOW to get the answer

Answer 5

x^3+8y^3

(x+2y) (x^2-2yx+4y^2)

Answer 6

=x^3 +(2y)^3
this is in the form of a^3 +b^3 =(a+b)(a^2+ab+b^2)
=(x+2y)(x^2-2xy+4y^2)

Answer 7

y^3=x^3/8
then
y=3under root(x^3/8)

Answer 8

x^3+8y^3
=x^3+(2^3)(y^3)
=x^3+(2y)^3
=(x+y)(x^2-xy+y^2)

Answer 9

cube root the question. it will leave you with 3root x+8y.

Answer 10

Just combine like terms (just add them).