(4x + 5y)^2
2007-01-13 20:25:53
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answer #1
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answered by The little "T" 3
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the product of the extremes is 16 x 25=400
we have to spilt the middle term 40 in sucha a way that when multiplied the twoparts should produce an answer of the product of extremes (i.e) 400.
now 40=20+20 as wells as 20 x 20=400
so spliting itwe can write this as
16x^2+20xy+20xy+25y^2
taking commn terms ans simplifying we get
4x(4x+5y)+5y(4x+5y)
=(4x+5y)^2
2007-01-13 06:02:56
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answer #2
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answered by srinsrinsri 2
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16x^2+40xy+25y^2 is given expression,
This can also be written as
(4x)^2+2*4x*5y+(5y)^2
This is in the form of a^2+2ab+b^2=(a+b)^2
Here,a=4x,b=5y.
.:16x^2+40xy+25y^2=(4x+5y)^2
=(4x+5y)*(4x+5y)
2007-01-13 02:13:10
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answer #3
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answered by shreya i 2
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16x^2+40xy+25y^2
(4x+5y)^2
2007-01-13 02:36:15
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answer #4
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answered by SHIBZ 2
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Given exp.=(4x)^2+2.4x.5y+(5y)^2
=(4x+5y)^2 ans
2007-01-13 01:46:44
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answer #5
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answered by alpha 7
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Repeat question?
Free points?
(4x + 5y)^2
Watch and see at least 2 more people post the exact same thing.
2007-01-13 01:29:02
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answer #6
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answered by Anonymous
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16 x^2 + 40 xy + 25 y^2 = (4x+5y) (4x+5y) = (4x+5y)^2
2007-01-13 01:34:02
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answer #7
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answered by maussy 7
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16x² + 40xy + 25y²
(4x + 5y)(4x + 5y)
(4x + 5y)²
- - - - - - - -s-
2007-01-13 01:39:20
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answer #8
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answered by SAMUEL D 7
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(4x+5y)(4x+5y)
(4x+5y)^2
2007-01-13 03:36:37
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answer #9
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answered by Anonymous
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ditto.
2007-01-13 01:31:27
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answer #10
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answered by S. B. 6
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