factor 16x^2+40xy+25y^2?

Question

thank you

Answer 1

16x² + 40xy + 25y²

16x² + 20xy + 20xyy + 25y²

4x(4x + 5y) + 5y(4x + 5y)

(4x + 5y)(4x + 5y)

(4x + 5y)²

- - - - - - - -s-

Answer 2

Okay... easy

Look for common factors ...

What number can you multiply to get 16 ? , What number can you multiply to get 25 and if you multiple each of them together and multiply it by 2 will you get 40

(16X^2+40xy+25) ==

lets try 4 and 5

4*4 gets you 16
5*5 gets you 25
4*5 = 20 * 2 = 40

so 4x* 4x = 16X ^2
5 x* 5x = 25y ^2

4x*5y = 20xy * 2 = 40xy

(4x+5y)^2

FOIL IT TO SEE IF IT WORKS

4x*4x + 4x*5y+4x*5y+5y*5y = 16x^2+40xy+25y^2

Answer 3

25x² - 81y² = (5x - 9y)(5x + 9y) - - - - - - - - - - - - - x² - 24x + 40 8 the middle term is - 24x discover the sum of the middle term multiply the 1st term a million circumstances the final term 40 8 equals 40 8 and element factors of 40 8 = a million, 2, 3, 4, 6, 8, 12, sixteen 24 40 8 - sixteen and - 8 fulfill the sum of the middle term insert - 16x and - 8x into the equation x² - 24x + 40 8 = 0 x² - 16x - 8x + 40 8 = 0 x(x - sixteen) - 8(x - sixteen) = 0 (x - 8)(x - sixteen) = 0 - - - - - - - - -s-

Answer 4

16x^2+40xy+25y^2
(4x+5y)^2

Answer 5

16x^2 + 40xy + 25y^2 = (4x + 5y)(4x + 5y)
= (4x + 5y)^2.

Answer 6

(4x + 5y)^2

Isn't it weird how even though one person already posts the correct answer, 5 other people feel the need to do the exact same thing.

Answer 7

16x^2 can also be written as (4x)^2
25y^2 can also be written as (5y)^2

this expression becomes (4x)^2 +___+(5y)^2
=(4x)^2+2 x (4x) x 5y + (5y)^2
this in the form of a^2 +2ab+b^2=(a+b)^2
let a= 4x and b=5y
it becomes
(4x+5y)^2

Answer 8

(4x + 5y)^2
the common factor is (4x + 5y)

Answer 9

(4x+5y)^2

Answer 10

(4x+5y)^2