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1. The weight of an object on the moon varies directly as its weight on the Earth. A person who weighs 150 pounds on Earth weighs 25 pounds on the moon. What is Jack's actual weight if he weighs 23 pounds on the moon?

2. If 27 chipmunks can consume 54kg of nuts in 45 days, how long will it take 72 chipmunks to consume 240kg of nuts?

2007-01-13 00:39:43 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

1. 150/25=6
An object weighs 1 pound on the moon for each 6 pounds on the Earth.
Jack's weight on the Moon is 23 pounds.
Jack's actual weight is 23*6=138 pounds on the Earth.

2. 27 chipmunks * 45 days = 54 kg of nuts
72 chipmunks * x days = 240 kg of nuts

72*x/240=27*45/54
x=75 days

2007-01-13 00:45:05 · answer #1 · answered by Salih D 1 · 0 0

2x^2 - 3x - 14 = 2 * (x^2 - 3x - 7) = 2 * (x - 3.5) * (x + 2) = (2x - 7) * (x + 2) = (2x^2 + 4x - 7x - 14) = 2x^2 - 3x - 14 The solutions for x are 3.5 and -2. when you consider that there is not any such issues as a damaging length we may be able to discard the answer -2, leaving us with: x = 3.5 ***************************** base = 3.5 * 2 = 7 top = 7 - 3 = 4 section = ((a million/2) * 7 * 4) = 14 ***************************** . once you get stuck on a factoring problem, do not waste any time. flow immediately to the quadratic formulation. you would possibly want to are growing: [3 +/- sqrt(9 - (4 * 2 * (-14)))] / 4 = [3 +/ (sqrt(9 + 112))] / 4 = (3 +/- 11) / 4 = 14/4 and -8/4 = 3.5 and -2 as values for x. That took 4 steps, do exactly it like this whenever you're unable to aspect right now. So the factors are (x - 3.5) * (x + 2) (and not in any respect forgetting about the unique 2x^2, the equation factors into: (2 * (x - 3.5) * (x - 2)) back, we throw out the x = -2, use x = 3.5 etc. it truly is the way so you might have carried out the mission. it would want to not be the fastest way there for this factoring however it is often the purely thanks to get the values of x. Have better faith in your self. in case you do not see the factors right now stop attempting and flow to the quadratic formulation. anticipate that you're precise and that it received't aspect. If as this one did, it would want to aspect what have you ever lost? solid success on your direction:) and performance faith in your self. BTW it truly is what I taught my own students to do when I taught algebra. pay interest to the voice of journey. lol . Gerry

2016-12-02 05:10:56 · answer #2 · answered by schebel 4 · 0 0

weight of object on moon'wm' is directly proportional to weight of object on earth'we'
so, wm/we = constant'k'
weight of man on earth 'we' = 150 pounds
weight of man on moon 'wm' = 25 pounds
wm/we = k
25/150 = k
1/6 = k
so the constant is 1/6

wt. of Jack on moon 'wm' = 23 pounds
let wt. of Jack on earth be 'e' pounds.
we = e
but,
wm/we = 1/6 (since, k= 1/6)
23/e = 1/6
implies, e = 23*6 (cross multiply)
e = 138 pounds
so, weight of jack on earth = 138 pounds.

2)let us get it in ratio form,
no of chipmunks - kg of nuts - no. of days
27 - 54 - 45
72 - 240 - x
ratio of no. of chipmunks : kg of nuts is direct proportionality.
ratio of no. of days : no.of chipmunks is inversely proportional.
so, compound ratio of 72:27 and 54:240 = 45:x
72*54:27*240 = 45:x
product of extremes = product of means
72*54*x = 27*240*45
x = 75 (on simplifcation.)
so,72 chimpmunks consume 240kg of nuts in 75 days.

2007-01-13 01:38:50 · answer #3 · answered by shreya i 2 · 0 0

27 chipmunks, 54 kg nuts,>>>>> 45 days

1 chipmunk, 54 kg nuts,>>>>> (45x27) days
1 chipmunk, 1 kg nuts,>>>>> (45x27)/54 days
72 chipmunks, 1 kg nuts,>>>>> (45x27)/(54x72) days
72 chipmunks, 240 kg nuts,>>>>> (45x27x240)/(54x72) days
. >>>>>> 75 days.

2007-01-13 00:56:24 · answer #4 · answered by curious 4 · 0 0

1. about 4 pounds

2007-01-13 00:44:06 · answer #5 · answered by palladin727 2 · 0 0

1. He weights 138 pounds on Earth.

2. Depends on how hungry they are..... And what time of year :) I HAVE NO IDEA on this one!!!

2007-01-13 01:04:47 · answer #6 · answered by ~~You Who~~ 2 · 0 0

#1. 138 Lbs.
#2. 83.33 days

2007-01-13 01:09:42 · answer #7 · answered by Maurine D 1 · 0 0

2. 75 days. i think.

2007-01-13 00:53:46 · answer #8 · answered by ? 3 · 0 0

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