Can you please SOLVE the following questions and SHOW the work? IT WOULD BE GREATLY APPRECIATED!
1. 8d-4d-2d-8=2d
2. a-5(a+10)-5=a
HELP GREATLY APPRECIATED!!!!
2007-01-12 23:30:12 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
2. a-5(a+10)-5 =a
a-5a-50-5=a
a-5a-55=a
a-5a-a=55
-5a=55
a=55/-5
a= -11
2007-01-12 23:42:40 · answer #1 · answered by Praveena 2 · 0⤊ 0⤋
When you are trying to solve algebraic equations, the best way of attacking them is to "do the same thing to both sides". So, using this method on the equations above, we get
1. 8d - 4d - 2d - 2d - 8 = 2d - 2d
(subtract 2d from both sides)
The only problem is that 8d - 4d - 2d - 2d = 0, and so this equation is now saying -8 = 0, which is clearly untrue. So I think you must have transcribed this problem wrongly, or left out some brackets, or someone else transcribed the problem wrongly, left out some brackets, or generally made a typo.
2. a - 5(a + 10) - 5 = a.
So, subtracting a from both sides we get
-5(a + 10) - 5 = 0.
Multiply by -1, gives
5(a + 10) + 5 = 0.
Divide by 5, gives
(a + 10) +1 = 0
So a + 11 = 0 (remove brackets, and add 10 and 1)
So a = -11.
Check:
-11 -5(-11 + 10) - 5 = -11 + 55 -50 - 5 = 44 - 55 = -11, as expected.
2007-01-12 23:49:39 · answer #2 · answered by Spell Check! 3 · 0⤊ 0⤋
With both questions, your ultimate goal will be to get the variable (d or a) isolated (by itself on one side). You can do this by multiplying, dividing, subtracting, and adding the same thing two both sides. Here's a way to solve the second one:
a-5(a+10)-5=a
Start by distributing the 5 over everything in the parenthesis.
a-5a-50-5=a
Combine like terms on each side:
-4a-55=a
Add 55 to each side:
-4a=55+a
Subtract a from each side:
-5a=55
Divide both sides by -5:
a=-11
Solve the first problem in the same manner. After showing all your work for the first problem, you will find that there will be no variable, therefore there is no solution. However, your teacher will still require you to show the work you did to figure out that there is no solution. Indicate the lack of an answer by drawing a 0 with a line through it diagonally.
2007-01-12 23:46:19 · answer #3 · answered by killingwish 4 · 0⤊ 0⤋
1. 8d-4d-2d-8=2d
8d-4d-2d-2d-8+8=2d-2d+8
0d=8
Clearly, as this is does not work with real numbers, you're probably studying this right now in algebra.
2. a-5(a+10)-5=a
a-a-5(a+10)-5=a-a
-5(a+10)-5=0
-5a-50-5=0
-55=5a
-11=a
2007-01-13 00:27:57 · answer #4 · answered by Kilroy 4 · 0⤊ 0⤋
8d-4d-2d-8=2d
or 2d-8=2d
Which is impossible, hence no solution.
a-5(a+10)-5=a
or a+5a-a = -50-5
or 5a = -55
or a = -11
2007-01-12 23:41:58 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋
8d-4d-2d-8=2d
6d-8=2d
-6d b/s
-8=-4d
I think you then divide -8 by -4 and that is the answer for d.
a-5(a+10)-5=a (multiply brackets)
-4a+50-5=a.
-4a+45=a (+ 4a b/s)
45=5a
a=9
I think thats right. Im no good at maths :-) But see if you think its right
2007-01-12 23:38:48 · answer #6 · answered by xMwahahahahahahax 3 · 0⤊ 0⤋
ok well i can help u on #2
multiply - 5 by the numbers in the parentheses
a-5a-50-5=a
then combine like terms
a-5a-45=a
then combine agian
-4a-45=a
then take the -4a over to the other side
-45=5a
then divide
-9=a
peace dogg
2007-01-12 23:44:35 · answer #7 · answered by dontwant2tellU 1 · 0⤊ 0⤋