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what is the value of x in the equation 3 to the exponent (4x-2)=27 to the exponent (x+2)

2007-01-12 21:43:37 · 7 answers · asked by a helpless gal 1 in Science & Mathematics Mathematics

7 answers

I hate math, thats why you should get a graphic calaculator and plug in the equations.

Fares Alsagri

2007-01-12 21:51:42 · answer #1 · answered by fox 5 · 0 0

what u mean by to the exponent x+2 at the end of the sentence? u mean 3^(4x-2)= 27? solve x?

2007-01-12 21:49:26 · answer #2 · answered by Kirk 2 · 0 0

X = 8

2007-01-12 22:15:26 · answer #3 · answered by Brenmore 5 · 0 0

x = 8

You simply make the bases the same.
Since 3^3 = 27, you can make the equation into:

3^(4x-2) = 27^(x+2)
3^(4x-2) = (3^3)^(x+2)
3^(4x-2) = 3^(3*(x+2))
3^(4x-2) = 3^(3x+6)

With the bases the same, you can make the exponents equal to each other.
4x-2 = 3x+6
using algebra, x = 8

2007-01-12 21:49:27 · answer #4 · answered by Anonymous · 1 0

3^(4x - 2) = 27^(x + 2)

= (3^3)^(x + 2)

= 3^[3(x + 2)], because a^b^c = a^(b*c) = a^(bc)

Both sides are now 3 raised to a power,
so the powers must be equal.

Therefore, 4x - 2 = 3(x + 2)
or, 4x - 2 = 3x + 6
so, x = 8.

2007-01-12 21:54:08 · answer #5 · answered by falzoon 7 · 0 0

3^(4x-2) = 27^(x+2)
I don't remember but i think it has to do with log...something
I've been outta school for 17 years now
(4x - 2) log3 = (x + 2) log27
4x - 2= (x + 2)log(27/3)= (x + 2) * 3
4x - 2= 3x + 6
x = 8

2007-01-12 23:10:49 · answer #6 · answered by Anonymous · 0 0

I think the answer is 54

2007-01-12 21:53:30 · answer #7 · answered by ☺C☺h☺a☺r☺l☺o☺t☺t☺e 3 · 0 0

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