Find the length of one side of a square with 8 m diagonal.
2007-01-12 21:41:18 · 9 answers · asked by a helpless gal 1 in Science & Mathematics ➔ Mathematics
8 m diagonal makes it a triangle with hypo. of 8m and opposite and adj sides which must be equal because it is a squre there fore opp. and adj are equal so are there angles cos45 = x/8
x = 8cos45
x = 5.657
2007-01-12 21:45:29 · answer #1 · answered by Anonymous · 3⤊ 0⤋
The 8 m diagonal divides the square into 2 right angled triangles.
Let the side of the square = x
x^2 + x^2 = 8^2
2 x^2 = 64
x^2 = 32
x = square root of 32.
a number between 5 and 6, you can finish it from here
2007-01-13 06:08:16 · answer #2 · answered by rosie recipe 7 · 0⤊ 0⤋
4
2007-01-13 05:44:42 · answer #3 · answered by Ojdeh 2 · 0⤊ 1⤋
Let side of a square be x
All sides of the square are equal
Diagonal=8m=hypotenuse
By pythagoras theorem
x^2+x^2=8^2
2 times x^2=64
x^2=32
x= square root of 32
x= 5.6568
therefore side of the square is 5.6568 m
2007-01-13 06:35:39 · answer #4 · answered by anand v 1 · 0⤊ 0⤋
The diagonal of a square is the side multiplied by root of 2 = 1.414 so the side is 8/1.414 = 5.66 m
2007-01-13 06:30:38 · answer #5 · answered by maussy 7 · 0⤊ 0⤋
Let x = length of side of square.
Using Pythagoras' theorem,
x^2 + x^2 = 8^2
Therefore, 2x^2 = 64
so, x^2 = 64/2 = 32
Thus, x = sqrt(32) = sqrt(2*2*2*2*2) = 4*sqrt(2)
2007-01-13 06:01:00 · answer #6 · answered by falzoon 7 · 0⤊ 0⤋
solve it this way...you know the diag is 8 and it's a square...so you have to right angle triangles with one side given...try that if you need to know the formula let me know...it's always best when you try on your own first
2007-01-13 05:52:14 · answer #7 · answered by Robert P 6 · 0⤊ 0⤋
2X^2=8^2
X=5.657 m
2007-01-13 05:45:43 · answer #8 · answered by laila 2 · 1⤊ 0⤋
5.657
2007-01-13 05:48:43 · answer #9 · answered by phil 2 · 0⤊ 0⤋