1^(1/0) = ?
x^(0)=1
2007-01-12 19:34:32 · 13 answers · asked by rajesh bhowmick 2 in Science & Mathematics ➔ Physics
1/0=un defined or infinity
x^(0) =1
so it will be any number the answer is one
1^(infinity)=infinity of 1
that is 1*1*1*1*......
so how many one we multiply the answer will be 1
answer is
1^(1/0)=1
2007-01-12 19:52:40 · answer #1 · answered by fervej 2 · 1⤊ 0⤋
1^(1/0)= undefined. You cant have 0 as denominator
x^0=1
2007-01-13 03:40:18 · answer #2 · answered by Anonymous · 0⤊ 1⤋
any value raise to the power 0 is 1.
1^(1/0)=1
let 1/0=n
we know that 1 raise to the power any value is 1 only.
so
1^n=1
=> 1^(1/0)=1
2007-01-13 12:46:28 · answer #3 · answered by PCMCPPE 1 · 0⤊ 0⤋
1^ (infinity) = 1.
x^0 = 1
2007-01-13 03:39:23 · answer #4 · answered by Poornima G 2 · 0⤊ 0⤋
You cant have 1/0 its undefined. the second one is 1.
2007-01-13 03:37:37 · answer #5 · answered by kingshighway77 2 · 1⤊ 0⤋
nothing
beacuse 1/0 is undefined
2007-01-13 05:11:26 · answer #6 · answered by 1145 2 · 0⤊ 0⤋
1/0 is not-defined.so this is the indeterminate form. that type of problems are solved in the higher mathematics.
second answer is 1.
2007-01-13 05:47:24 · answer #7 · answered by megha 1 · 0⤊ 0⤋
for the secon one it is one as anything has power of zero is always one like e^0=1
2^0=1
etc......
so x^0=1 oki
2007-01-13 05:26:14 · answer #8 · answered by smile 1 · 0⤊ 0⤋
1/0 is not defined
x^0is definetely 1
2007-01-13 12:44:11 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Weren't the 10 answers you got under Mathematics enough?
2007-01-13 03:43:57 · answer #10 · answered by Helmut 7 · 0⤊ 0⤋