What values for x must be excluded in the following fraction?
(x-2)/(x-3)
I want it solution. because, I am making notes so tell me writte solution..
Thanks.
2007-01-12 19:15:05 · 8 answers · asked by Pushpendra C 1 in Science & Mathematics ➔ Mathematics
division by zero is not allowed, which should allow you to figure out the answer.
2007-01-12 19:20:24 · answer #1 · answered by arbiter007 6 · 0⤊ 0⤋
x-3=0 x=3
2007-01-12 19:24:59 · answer #2 · answered by farfar 2 · 0⤊ 0⤋
perhaps an answer would be 3...
I'm not sure if there's another answer though...
for this question, well, i think you have to use trial and error. since fractions serve as another way of expressing division, you have to take note of the denominator. the denominator should not be equal to zero. otherwise, the value is undefined. remember:
0 can be divided by other numbers but it can never divide another number.
e.g. 0/2 = 0 but 2/0 = undefined
therefore, for your problem, the 3 is an obvious answer:
(x-2)/(x-3)---->(3-2)/(3-3)=1/0---->undefined
2007-01-12 19:26:26 · answer #3 · answered by changing_sky 2 · 1⤊ 0⤋
Ans is 3.
=> (x-2) / (x-3)
=> when x=3, (x-2) / (3-3) = (x-2) / 0 which is undefined.
Hence, x=3 must be excluded.
2007-01-12 19:48:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
X-2/X-3 multiply the top and bottom by X-3
2007-01-12 19:19:40 · answer #5 · answered by laxgod55 2 · 0⤊ 1⤋
3.
because anything divided by 0 is undefined yet :)
2007-01-12 19:33:49 · answer #6 · answered by pigley 4 · 0⤊ 0⤋
3 because you cannot divide by zero.
2007-01-12 19:20:15 · answer #7 · answered by crazy_tentacle 3 · 0⤊ 0⤋
3, since the denum can't be zero
2007-01-12 19:20:05 · answer #8 · answered by dragontail_ys 1 · 0⤊ 0⤋