1^(1/0) = ?
x^(0) = 1
2007-01-12 19:07:14 · 16 answers · asked by rajesh bhowmick 2 in Science & Mathematics ➔ Mathematics
I do not agree with stan w's response. "when you see division in exponents it is the same as subtraction" It should be "when you see subtraction in exponents it is the same as division". Those are different statements. Division in exponents is the same as roots. x^(1/2)=√2. Therefore x^(1/0) is the zeroeth root of x, whatever that means.
2007-01-12 20:43:46 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
1
2007-01-12 19:10:31 · answer #2 · answered by ravi t 1 · 1⤊ 1⤋
when you see division in exponents it is the same as subtraction...these are unique cases and are often confused with the regular rules of math. 1^(1/0) can be rewritten as:
1^(1-0) = 1^1/(1^0)
since 1^0 is 1
it is simplified to 1/1 or just 1
Think of it as 2^(2/1), this is rewritten as:
2^2/(2^1) = 4/2 =2
this answer can be calculated by subtracting the exponents:
2^(2-1)= 2^1 = 2
The second equation x^(0)=1, x can be any number
FYI, unlike a majority of the other responses, when talking exponents, any number x^(n/0) where n can be any whole number, n/0 is not "undefined" you simply perform the subtraction to get x^(n-0). There is no real division when dealing with exponents..it is either addition (for muliplication) and subrtraction (for division)
2007-01-12 19:34:52 · answer #3 · answered by stan w 3 · 1⤊ 0⤋
1/0=0, any base to the power of 0 is 1.
2007-01-12 19:14:07 · answer #4 · answered by compstuft 2 · 1⤊ 2⤋
The first formula is undefined, since division by zero results in infinity for any number. You could say that 1 to any power equals 1, but your math teacher wouldn't like it because of the division by zero.
PS: I think Stan W is mistaken, math degree or not. The notation 1 ^ (1/0) is telling you to first perform (1/0) and then do the exponentiation. N ^ (1/3) means to take the cube root of n!
2007-01-12 19:16:12 · answer #5 · answered by hznfrst 6 · 0⤊ 2⤋
1/0=infinity
1^infinity= 1
2007-01-12 19:16:05 · answer #6 · answered by laila 2 · 2⤊ 1⤋
1/0 = infinity
1^infinity means multiply 1 with 1 infinite times
that'll still give u one
so, 1^(1/0) = 1
2007-01-13 04:33:33 · answer #7 · answered by sushobhan 6 · 0⤊ 1⤋
1^(1/0) is discontinous; you could use limits to find values as 1^(1/x) approaches zero to approximate this function but it is undefined at this point.
x^(0)=1 for any value pluged into x
You could plug (x^(0)) into the top equation too because 1 = x^(0); in other words, x^(0)^(1/0) but it would still be undefined without using limits and advanced Calculus for the power of 1/0.
2007-01-12 19:25:26 · answer #8 · answered by Anonymous · 1⤊ 1⤋
1 x 1/0 = 1
1 (0) = 1
Both equations equal "1"
2007-01-12 19:12:30 · answer #9 · answered by Truth D 4 · 0⤊ 2⤋
1 / 0 = infintity
1^ infinity = undefined
2007-01-13 00:46:24 · answer #10 · answered by a girl frm nowhere 2 · 0⤊ 0⤋