I am working on a science fair experiment, and my teacher offered to create a solution for me. I went in, and she was too busy to help so now I am on my own. I went and bought 28% hydrochloric acid but I need to dilute it to 0.1 M, does anyone know how much water Iand how much acid it will take to dilute it to 0.1 M? (How many grams of acid mixed with how many mL of water to get it diluted).
I was answered this before:
"Hydrochloric acid is anywhere from 28% to 36% HCl, so you'll have to dilute it by roughly 1:60 to get a solution that is an acceptable simulation of gastric juice for your purposes."
But, what does 1:60 mean?
2007-01-12 18:23:19 · 4 answers · asked by dani_es_bonita 1 in Science & Mathematics ➔ Chemistry
28% HCl contains 280g HCl per litre.
0.1M HCl contains 36.5/10 = 3.65g HCl per litre.
So, you have to dilute the purchased HCl by 280/3.65 = 1:77.
As others have advised, add the acid to the water. Add 10g of 28% acid gently to 770ml water. If using a volumetric measure, then add about 8.7ml 28% acid to 770ml water, because 28% hydrochloric acid has a density of about 1.15kg/litre.
2007-01-12 21:09:42 · answer #1 · answered by JJ 7 · 0⤊ 1⤋
I go along with timmytoes. I part acid 60 parts water.
2007-01-12 18:31:09 · answer #2 · answered by Floyd B 5 · 0⤊ 0⤋
one part hydrochloric acid to 60 parts water.
2007-01-12 18:27:21 · answer #3 · answered by timmytoes 2 · 0⤊ 0⤋
I agree with the above, but add acid to water..never water to acid..
2007-01-12 18:35:28 · answer #4 · answered by jst4pat 6 · 0⤊ 0⤋