How do I solve this?

Question

ax + bx = a^2 + 2ab +b^2?

I can not understand this problem. My book does not even explain it well. Can someone please show me how to solve this. ^^

For your 411, My parents can't even understand it, and they agree that the book does not explain it well. If your not going to help, then don't bother answering this question...jeez.

Answer 1

Apparently, they want you to factor this....

ax + bx = (a + b)x

a^2 + 2ab + b^2 = (a + b)^2

So, rewrite your problem as (a + b)x = (a + b)^2, which simplifies to x = a + b

Answer 2

It is very easy Maria
ax+bx=a^2+2ab+b^2
=> x(a+b)=(a+b)^2
=>x=(a+b)^2/(a+b)=a+b

Answer 3

ax + bx = a^2 + 2ab +b^2
x(a+b)=(a+b)^2 divide both sides by a+b
x=a+b

Answer 4

ax+bx=(a+b)x

so substract it from both sides

0 = -(a+b)x +(a+b)^2

0 = (a+b)((a+b)-x)

divide both sides by (a+b)

0 = (a+b-x) ---> x = a+b

check
a(a+b) +b(a+b)= a^2 +ab +ba +b^2 = a^2 +2ab +b^2

Answer 5

as other people have noted"


/************************************************************/
x = a + b, with the condition

{ x not equal to 0 } <==== necessary condition
OR
"a" is not equal to "b".

There *was* a step
x (a + b) = (a + b)^2
followed by dividing both sides by (a + b) ...
however, this is valid ONLY when (a + b) not = 0
/************************************************************/


This might sound "picky", but

{x = 0} leads to a contradiction which means it is NOT a solution.

{ x = 0 } =>
{ (a + b)=0 }

but if (a + b)=0 then x = 12 satisfies the equation ...

which contradicts the original statement "x = 0"

when contradictions occur, something's wrong;

to avoid contradictions, it MUST be the case that x not equal 0.

which implies that "a" is not equal to "b".

Answer 6

~first, substitute n's for the a's, q's for the x's, y's for the b's and check you book again. You may just be making a spelling error. If that doesn't work, talk to your teacher. That's what they get paid for. Since the book can't help because you are too lazy to spend the time to learn the material, or to learn how to learn the material, maybe you should just drop the course.

Answer 7

I assume the question is to solve for x... Factor both sides!
(a+b)x = (a+b)²

Divide by the common factor (a+b)...
x = a+b.

Answer 8

Factor to arrive at
x(a+b)=(a+b)(a+b)
Hmmm....
x=(a+b)