How much energy do u need to boil water and how much energy was realesed from the atomic bomb?

Question

Doing a history project!

At STP
The water is at 0 degrees celcius

Answer 1

1 calorie is needed to raise the temperature of one mL of water 1 degree Celsius.
1 calorie = 4.18400 joules

So to boil 1mL of water from 0 degrees 418.4 joules are needed.

84,000,000,000,000,000 joules was the yield from Little Boy (84,000 Tera-Joules).

http://hypertextbook.com/facts/2000/MuhammadKaleem.shtml

So Little Boy was 2.0076e+14 times more energy then what is required to boil 1mL of water.

Best answer?

Answer 2

The boiling point of water is 100 C. The specific heat capacity of water is 1 cal gm^-1 deg C^-1. Therefore to compute the energy required to bring the water to boil we must know how many grams of water we have and what the current temperature is. The difference between this temperature in degrees centigrade and 100 degrees is then multiplied by the mass of the water in gm and the result will be the amount of energy in Calories.
In the atomic bomb the energy released is given by E =MC^2 where M is the mass and C is the velocity of light. For comparison purposes you could take the same mass of water that you heated to boiling and convert it all to energy by the above formula. The answer will be in ergs and there are
4.186 ergs cal^-1. Work through the arithmetic and you will get your comparison. I do not know how much mass was converted in the first atomic bombs, but this work I have done will provide a comparison between nuclear power and heat.

Answer 3

The amount of enerdy it takes to boil water depends on several diffrent factors. However, the amount of energy needed to raise 1 gram of water 1' Celcius is called a calorie (the same unit of measurment used in food. More calories in food= more energy required to break that food down). To find how much energy it will take to boil water, you must know the starting temperature and the point at wich water will boil. (Since you're a student- I'll let you find the rest)

The atomic bombs dropped on Japan durring WWII released the equivelent of 1 million sticks of TNT dynamite.

Answer 4

Clarification. The answers concerning the amount of energy to heat water is correct
1 gram water (1 cubic centimeter or 1 mL) heated 1 degree C = 1 cal (same definition for BTU and degree F, and either pounds or ounces, I forget)

but... it is very important to know that the amount need to raise the water to the boiling point is not related to the energy required to actual boil (vaporize) the water. This is known as the latent heat of vaporization and it far exceeds the specific heat of water. This depends on the pressure of the water/steam. (The temperature at which water will boil depends on the pressure. Temperature and pressure define the phase of the water. See phase diagrams in thermodynamics)

Answer 5

Food calories are Kilo-calories or large calories.
A small (normal) calorie will normally heat one gram of liquid water through one Celsius degree.
Heat of fusion of water at 0 degrees Celsius = 79.71 calories per gram. This is the amount of energy needed to change one 0 degree C. gram of ice into one 0 degree gram of liquid water.
Heat of vapourization of water at 100 degrees C. = 539.55 calories per gram. This is the amount of energy needed to change one 100 degree C. gram of liquid water into one 100 degree gram of water vapour.
While heat is usually measured in calories, energy is usually measured in Joules (Watt-seconds). There are 4.1868 Joules in a calorie.
So to boil ice from 0 degrees C. you need (79.71 + 100 + 539.55) * 4.1868 = 3011 Joules of energy per gram.
To boil liquid water from 0 degrees C. you need (100 + 539.55) * 4.1868 = 2678 Joules of energy per gram.
As for atomic and nuclear bombs; I do not like them.

Answer 6

You have a best answer, but note that the calories used in food diets is 1000 times the size of the calorie used in heat measurement.