I need help -- my friend asked me to help her, she's over AIM. I tottaly forgot how to do this:
y(squared)+12y+32
10 pts to anyone who can do the problem :)
2007-01-12 12:46:11 · 10 answers · asked by I think... 6 in Science & Mathematics ➔ Mathematics
I assume you are supposed to factor this
y^2 + 12y + 32
So look at the factors of 32 and see which ones combine to get 12
8*4=32, and 8+4=12, so your answer is (y + 4)(y + 8)
2007-01-12 12:50:01 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Do need to factor the expression?
First: multiply the 1st and last coefficient (1*32 = 32). find two numbers that give you 32 when multiplied and 12 (middle coefficient) when added/subtracted. The numbers are: 8, 4
Sec: rewrite the expression with the new middle numbers...
y^2 + 8y + 4y + 32
Third: group "like" terms and factor...
(y^2 + 8y) + (4y + 32)
y(y + 8) + 4(y + 8)
(y + 4)(y + 8)
2007-01-12 21:01:57 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
y² + 12y + 32 = (y + 4)(y + 8)
2007-01-12 20:52:02 · answer #3 · answered by Northstar 7 · 1⤊ 0⤋
y^2+12y+32
= y^2+4y+8y+32
=y(y+4)+8(y+4)
=(y+4)(y+8)
2007-01-12 20:51:47 · answer #4 · answered by hirunisha 2 · 1⤊ 0⤋
(y + 8) (y + 4)
2007-01-12 21:14:35 · answer #5 · answered by koz 2 · 0⤊ 0⤋
(y + 8) (y + 4)
2007-01-12 20:50:17 · answer #6 · answered by e_kueh 2 · 0⤊ 0⤋
y^2 + 12y + 32 = 0
(y + 8)(y + 4) = 0
y = -4 or -8
2007-01-12 20:50:09 · answer #7 · answered by Tom :: Athier than Thou 6 · 0⤊ 2⤋
(y+4)(y+8)
2007-01-12 20:50:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(y+4)(y+8)
2007-01-12 20:50:16 · answer #9 · answered by 7 · 0⤊ 0⤋
your teacher can and you need to study............
2007-01-12 20:49:53 · answer #10 · answered by cork 7 · 0⤊ 2⤋