haha... you are too witty... you should come to my abode for some tea and crumpets...
2007-01-12 12:39:27
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answer #1
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answered by Anonymous
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pointy has the final thought, yet you nonetheless could coach that sqrt{3} is irrational. you may coach that the sq. root of any top variety is irrational in a similar fashion which you coach it for the sq. root of two. assume that (m/n)^2 = p , the place p is a primary. (you will use p=3). greater suitable, assume that the fraction (m/n) is totally decreased : GCD(m,n)=a million . Then: m^2 = p*n^2 .for that reason, p divides m^2. on condition that p is fundamental, this implies that p divides m. Say m=ok*p. we now have the equation: (ok^2)(p^2)/(n^2) = p . which components us: p*ok^2 = n^2. for an identical reason as before, we get that p divides n. Say j*p=n . Our unique fraction: (m)/(n) = (ok*p)/(j*p) . Our unique assumption that the fraction exchange into in maximum simplified variety has been contradicted. for that reason, the sq. root of p could be irrational.
2016-12-16 03:18:12
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answer #2
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answered by ? 4
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Mine is the square root of 1. =)
2007-01-12 12:45:05
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answer #3
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answered by Anonymous
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I love geek humor!
Now you just need to find a girl who loves sqrt(2) as much as you do. I predict you will multiply and have 2 children.
2007-01-12 12:44:30
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answer #4
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answered by Puzzling 7
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Wow you are sooooo unique
You should win the Nobel Peace prize
you rebel you.......
2007-01-12 12:38:40
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answer #5
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answered by Anonymous
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u are u and thats ur fav number. thats u. and if peoples call u a nerd just don't listen or as a guy named Cameron said, "u suck live with it." but thats just him. be u!
2007-01-12 12:41:37
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answer #6
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answered by i2OOO s 1
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you are irrational and apparently fond of making terrible puns as well.
2007-01-12 12:39:16
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answer #7
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answered by Anonymous
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Really more of a nerd.
I am a physicist
2007-01-12 12:38:29
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answer #8
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answered by shadouse 6
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Very punny.
2007-01-12 12:38:34
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answer #9
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answered by Jim Burnell 6
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nope, just a lonely, lonely man....
2007-01-12 12:39:17
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answer #10
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answered by Anonymous
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