Light strikes the surface of a prism, (index of refraction) n = 1.9, If the prism is surrounded by a fluid...

Question

Light strikes the surface of a prism, (index of refraction) n = 1.9, If the prism is surrounded by a fluid, what is the maximum index of refraction of the fluid that will still cause total internal reflection within the prism?...the figure looks like a right triangle with the hypotenuse going from top left to bottom right. The light strikes the side of the triangle in the perpendicular, and it leaves the prism at an angle perpecdicular to the bottom line.

If you could please come up with an answer and even possible explain how you got it..that would be great!!!!! Thanks!

Answer 1

Snell's Law says n1sini = n2sinr. For Total internal reflection r = 90, so sinr =1. Then 1.9sini = n2. Find n2, but I'm not sure what is i. If the triangle is isosceles then i = 45 deg. Make sure your calculatir is in degree mode. i is probably 45 deg because you say the reflected ray goes straight down

Answer 2

Given


ni = 1.9 , theta i = 45 degrees

nr = ?, theta r = 90 degrees

from Snell's law

ni sin theta i = nr* sin theta r


nr = ni sin theta i / sin theta r

nr = ni sin theta i / sin90

= ni sin theta i
= 1.8 sin 45

= 1.2728

the refracive index of the fluid so that the total internal reflection takes place is 1.2728

Answer 3

This shape of a prism is such that it disperses white gentle into ingredient colorings. Rain drops disperse gentle by utilising entire inner mirrored photograph (TIR) thereby producing rainbow. Our eye lens isn't of the form that could disperse gentle. Eye lens varieties a pointy, actual and inverted photograph on the retina, the retina communicates this photograph to the ideas by utilising utilising the optic nerve. wish that helps :)