Evaluate this equation?

0 ⤊

∫ log3x
2x dx

2007-01-12 11:44:54 · 3 answers · asked by Georgette W 1 in Education & Reference ➔ Homework Help

∫{ln(3x)} 2x dx ={ln(3x)} x^2 - ∫(1/x)* x^2 dx
=x^2 ln(3x) -∫ x dx
= x^2 ln(3x) -x^2/2
=x^2(ln(3x)-(1/2))

2007-01-12 15:58:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋

I don't understand what the 2x dx is doing at the bottom either.
Sorry.

2007-01-12 14:06:42 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋

let me just clarify this: what is 2x dx doing at the bottom?

2007-01-12 12:55:56 · answer #3 · answered by bluewarrior 2 · 0⤊ 0⤋