Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A fu

Question

Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
•16 represents ½g, the gravitational pull due to gravity (measured in feet per second 2).
•v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
•s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
Answer:




b) The ball will be how high above the ground after 1 second?
Answer:
Show work in this space.




c) How long will it take to hit the ground?
Answer:
Show work in this space.

Answer 1

a:s=-16*t^2+32*t

b
s=-16+32
=16ft


c
The roots of
0=-16*t^2+32*t
are t=0 (starting)
and t=2

j

Answer 2

enable u=preliminary velocity of ball v=very final velocity of ball if ball is shot up, u^2-v^2=2*g*h g=gravitational accelaration=9.8m/(s^2) optimal top, H=u^2/(2*g) time to realize H,t=u/g entire time to bypass upto H and return on floor=2t=2u/g